500=-16t^2-2t+539

Solution for 500=-16t^2-2t+539 equation:

500=-16t^2-2t+539

We move all terms to the left:

500-(-16t^2-2t+539)=0

We get rid of parentheses

16t^2+2t-539+500=0

We add all the numbers together, and all the variables

16t^2+2t-39=0

a = 16; b = 2; c = -39;
Δ = b2-4ac
Δ = 22-4·16·(-39)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-50}{2*16}=\frac{-52}{32}
=-1+5/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+50}{2*16}=\frac{48}{32}
=1+1/2
$